[Level 1] How to trace the source code more efficient.

If you want to trace python call stack, you could get call sequence by using call_seq module. You could download call_seq from pypi website. https://pypi.python.org/pypi/call_seq/0.0.1 After you download it, you could prepare the python script like following. 
python from call_seq import CallSeq
trail = CallSeq()
trail.set_trace()
# the code you want to trace.
trail.unset_trace()
trail.dump_to_file('output.json')
After you create the output json file, then you could use browser module of call_seq to get visualization of call sequence. 
$ python -m call_seq.browser ./output.json

Wish this helps.

regards,
Stanley Huang

Comments

Post a Comment

Popular posts from this blog

[Level 2] Shell Interactive With Zenity Episode 5 -- list

Image
If you want to give a list for user to choose, you can use the option "--list". The command synopsis as below: SYNOPSIS      zenity  --list [--title=title] [--window-icon=path] [--width=width]    [--height=height] [--timeout=seconds] [--column=text] [--checklist]       [--radiolist] [--separator=character] [--multiple] [--editable] [--print-column=number] [--hide-column=number] Just like " --calendar ", if you press "ESC" key or click button "Cancel", the return code will be "1". If you select one option and click "OK", zenity will response the option and return the code will be "0". And also the same effect about the options "--title", "--timeout"...etc, for saving your time, please refer to the previous post " [Level 2] Shell Interactive With Zenity Episode 1 -- calendar ", too. About "--multiple" and "--separator", please refer to tht previous post " [Lev...
Read more

[Level 2] iif in Python

If you want to implement iif in Python, please refer to the following sample code: #!/bin/env python def iif(b): return 'It\'s True' if b else 'It\'s False' print iif(True) print iif(False) And the following sample, guess what will you get! #!/bin/env python b = True print 'b: %s' % 'Ture' if b else 'False' b = False print 'b: %s' % 'Ture' if b else 'False' Result: $ ./iif.py b: Ture False The second result is "False", not "b: False". Why??? Because the prededence of string concatenation is higher than if. Therefore you need to use () to make it correct. #!/bin/env python b = True print 'b: %s' % 'Ture' if b else 'False' b = False print 'b: %s' % ('Ture' if b else 'False') Wish this helps. regards, Stanley Huang
Read more