[Level 2] iif in Python

If you want to implement iif in Python,
please refer to the following sample code:

#!/bin/env python
def iif(b):
  return 'It\'s True' if b else 'It\'s False'

print iif(True)
print iif(False)

And the following sample, guess what will you get!

#!/bin/env python
b = True
print 'b: %s' % 'Ture' if b else 'False'
b = False
print 'b: %s' % 'Ture' if b else 'False'

Result:

$ ./iif.py 
b: Ture
False

The second result is "False", not "b: False". Why???
Because the prededence of string concatenation is higher than if.
Therefore you need to use () to make it correct.

#!/bin/env python
b = True
print 'b: %s' % 'Ture' if b else 'False'
b = False
print 'b: %s' % ('Ture' if b else 'False')

Wish this helps.
regards,
Stanley Huang