[Level 1] Encoding in Python script.
If there are some wording not for ascii, you should add # -*- coding: (encoding) -*-
to prevent compile error.
example error message:
File "./testEncoding.py", line 21
SyntaxError: Non-ASCII character '\xe6' in file ./testForLoop_2.6.py on line 21, but no encoding declared; see http://www.python.org/peps/pep-0263.html for details
e.g.
regards,
Stanley Huang
to prevent compile error.
example error message:
File "./testEncoding.py", line 21
SyntaxError: Non-ASCII character '\xe6' in file ./testForLoop_2.6.py on line 21, but no encoding declared; see http://www.python.org/peps/pep-0263.html for details
e.g.
#!/usr/bin/python2.6 # -*- coding: utf8 -*- ### chinese testing slang="有嘴說別人無嘴說自己" sword="嘴" ## error with encoding #for i in slang: # print i # use python shell to display encoding # ex. # >>> "有嘴說別人無嘴說自己" # '\xe6\x9c\x89\xe5\x98\xb4\xe8\xaa\xaa\xe5\x88\xa5\xe4\xba\xba\xef\xbc\x8c\xe7\x84\xa1\xe5\x98\xb4\xe8\xaa\xaa\xe8\x87\xaa\xe5\xb7\xb1\xe3\x80\x82' # >>> "嘴" # '\xe5\x98\xb4' l=len(sword) h=0 k=0 count=0 for item in slang: k=0 f=1 while k<l: if slang[h+k]==sword[k]: k+=1 continue else: f=0 break if f==1: count+=1 h+=1 if h>=(len(slang)-l): break print count
$ ./testEncoding.py 2 $Wish this helps.
regards,
Stanley Huang
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